Asked by Jean
find th quadratic fuction that has a vertix of (8.-3) and whose graph goest throught the point (-6, -395)
Answers
Answered by
Henry
V(8 , -3) , P(-6 , -395).
Y = a(x - h)^2 + K.
-395 = a(-6 - 8)^2 + (-3),
-395 = 196a - 3,
196a = -395 + 3,
196a = -392,
a = -392 / 196 = -2.
Eq: y = -2(x - 8)^2 - 3(Vertex form).
This parabola opens downward, because a < 0.
Y = a(x - h)^2 + K.
-395 = a(-6 - 8)^2 + (-3),
-395 = 196a - 3,
196a = -395 + 3,
196a = -392,
a = -392 / 196 = -2.
Eq: y = -2(x - 8)^2 - 3(Vertex form).
This parabola opens downward, because a < 0.
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