Question
An object is thrown upward from the top of an 80ft tower. The height h of the object after t seconds is represented by the quadratic equation h=-16t^2+64t+80
After how many seconds will the object hit the ground
After how many seconds will the object hit the ground
Answers
GPT 3.5
To find when the object hits the ground, we need to solve for h=0 in the equation h=-16t^2+64t+80:
-16t^2 + 64t + 80 = 0
Dividing by -16 to simplify:
t^2 - 4t - 5 = 0
Now, this quadratic equation can be factored as:
(t-5)(t+1) = 0
So the solutions are t=5 and t=-1. Since time cannot be negative, the object will hit the ground after 5 seconds.
-16t^2 + 64t + 80 = 0
Dividing by -16 to simplify:
t^2 - 4t - 5 = 0
Now, this quadratic equation can be factored as:
(t-5)(t+1) = 0
So the solutions are t=5 and t=-1. Since time cannot be negative, the object will hit the ground after 5 seconds.