Question

object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula
h(t)=−16t^2+v0t+h0 feet
where t is the amount of time in seconds after the ball was thrown. Also, the velocity of the object is given by
v(t)=−32t+v0. feet per second

When one uses the metric system, the equations become
h(t)=−4.9t^2+v0t+h0 meters
and
v(t)=−9.8t+v0 meters per second.



An object is projected upward from a height of 33 feet at a velocity of 97 feet per second.


Find the velocity of the object when it hits the ground.

Answer 1

the same as when it went up.

Answer 2

oops. not so, due to h0

so, find t when h(t)=0
then use that to get v(t) at that time.