Asked by Sharon
If an object is thrown upward with an initial velocity of 96 feet/sec, it's height after t sec is given by h=96t-16t^2. Find the number of seconds before the object hits the ground.
Answers
Answered by
bobpursley
When it hits the ground, h is again zero
h=0=96t-16t^2=16t(6-t)
so t=6seconds
h=0=96t-16t^2=16t(6-t)
so t=6seconds
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