Asked by Anonymous
4kg object thrown upward with a speed of 40m/s what is the maximum height that it can reach
Answers
Answered by
oobleck
v^2 = 2gh
so max height is h = v^2/(2g) = 1600/19.6 = _____
so max height is h = v^2/(2g) = 1600/19.6 = _____
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