Asked by Mary

A mixture contained CaCO3 and MgCo3. A sample of this mixture weighing 7.85g was reacted with excess HCl. The reactions are--
CaCO3 + 2HCl --> CaCl2 + H2O + CO2

MgCO3 + 2HCl --> MgCl2 + H2O + CO2

Is the sample reacted completely and produced 1.94L of CO2, at 25 degrees C, 785mmhg, whre were the percentages of CaCO3 and MgCO3 in the mixture?

So far, I got the moles of CO2 by using PV=nRT, which is .0817moles of CO2,

I don't kno what to do next.. can anyone PLEASE help!
Answered by SraJMcGin
NEED HELP will NOT get you help. Name it Chemistry or whatever it is.

Sra
Answered by Anonymous
___C12H22O11 (s) + ___H2SO4 (aq) → ___C(s) + ___H2O (l) + ___H2SO4 (aq)

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