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Container A contained a mixture that is 40% acid, while container B contained a mixture that is 60% acid. A chemist took some amount from each container, and mixed them. To produce 100 liters of mixture that is 17% acid, she needed to pour 70 liters of pure water to the mixture she got from containers A and B. How many liters did she take from container A?
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Let x be the number of liters taken from container A.
The total amount of mixture from both containers is x + (100 - x) = 100.
The total amount of acid in the mixture is 0.4x + 0.6(100 - x) = 17.
Solving for x, we get x = 40 liters.
Therefore, the chemist took 40 liters from container A.
The total amount of mixture from both containers is x + (100 - x) = 100.
The total amount of acid in the mixture is 0.4x + 0.6(100 - x) = 17.
Solving for x, we get x = 40 liters.
Therefore, the chemist took 40 liters from container A.
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