PE = 0.0061 kg * g * 0.017 m = 0.010 J
KE = PE = 0.010 J
A small solid sphere, with radius 0.25 cm and mass 0.61 g rolls without slipping on the inside of a large fixed hemisphere with radius 17 cm and a vertical axis of symmetry. The sphere starts at the top from rest.
(a) What is its kinetic energy at the bottom?
4 answers
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Haven't you made mistakes in two of those unit conversions? 0.61g = 0.00061kg not 0.0061kg, and 17cm = 0.17m not 0.017m.