Asked by maqbool
The mass of a solid sphere of metal 5cm in diameter is 6.25 kg. Find the mass of a spherical shell of same metal, the external diameter being 10cm and thickness 1 cm.
Answers
Answered by
Reiny
volume of the 5 cm sphere
= (4/3)π(5^3) = (500/3)π cm^3
volume of shell
= (4/3)π(10^3) - (4/3)π(8^3)
= (1952/3)π
since the mass is a function of the volume,
[ (1952/3)π] / [(500/3)π] = x/6.25
1952/500 = x/6.28
500x = 12200
x = 24.4 kg
check my arithmetic
= (4/3)π(5^3) = (500/3)π cm^3
volume of shell
= (4/3)π(10^3) - (4/3)π(8^3)
= (1952/3)π
since the mass is a function of the volume,
[ (1952/3)π] / [(500/3)π] = x/6.25
1952/500 = x/6.28
500x = 12200
x = 24.4 kg
check my arithmetic
Answered by
Sachin
volume of the 5/2 cm sphere
= (4/3)π(5/2^3) = (625/6)π cm^3
volume of shell
= (4/3)π(5^3) - (4/3)π(4^3)
= (244/3)π cm^3
since the mass is a function of the volume,
(625/6)π × X = (244/3)π × 6.25
X = 48.8kg
= (4/3)π(5/2^3) = (625/6)π cm^3
volume of shell
= (4/3)π(5^3) - (4/3)π(4^3)
= (244/3)π cm^3
since the mass is a function of the volume,
(625/6)π × X = (244/3)π × 6.25
X = 48.8kg
Answered by
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fak u
Answered by
mother F
volume of the 5/2 cm sphere
= (4/3)π(5/2^3) = (625/6)π cm^3
volume of shell
= (4/3)π(5^3) - (4/3)π(4^3)
= (244/3)π cm^3
since the mass is a function of the volume,
(625/6)π × X = (244/3)π × 6.25
X = 48.8kg
= (4/3)π(5/2^3) = (625/6)π cm^3
volume of shell
= (4/3)π(5^3) - (4/3)π(4^3)
= (244/3)π cm^3
since the mass is a function of the volume,
(625/6)π × X = (244/3)π × 6.25
X = 48.8kg
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