Asked by Bobby
can someone break down how to take the integral of this problem?
20te^-10t dt
20te^-10t dt
Answers
Answered by
Tiffany
e^-10t dt -10te^-10t dt= te^-10t
e^-10tdt=(e^-10t)/-10
10te^-10tdt=(e^-10t)/(-10)-te^-10t
20te^-10t dt =(e^-10t)/(-5)-2te^-10t
e^-10tdt=(e^-10t)/-10
10te^-10tdt=(e^-10t)/(-10)-te^-10t
20te^-10t dt =(e^-10t)/(-5)-2te^-10t
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