Asked by Anonymous
A juggler performs in a room with a ceiling 2m abouve hand level. A. what is the maximum upward speed she can give the ball without hitting the celing.
B. what is the time spent in the air before the ball is caught?
B. what is the time spent in the air before the ball is caught?
Answers
Answered by
MathMate
A.
Equate potential and kinetic energies:
potential energy = mgh = mg(2) N-m
where g = acceleration due to gravity = 9.8 m/s²
kinetic energy = (1/2)mv²
Equate energies:
mgh = (1/2)mv²
solve for v (m/s)
B. t = v/g (deceleration by gravity)
Equate potential and kinetic energies:
potential energy = mgh = mg(2) N-m
where g = acceleration due to gravity = 9.8 m/s²
kinetic energy = (1/2)mv²
Equate energies:
mgh = (1/2)mv²
solve for v (m/s)
B. t = v/g (deceleration by gravity)
Answered by
Anonymous
(A) 6.3m/s
(B)1.3 s
(B)1.3 s
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