Question
A juggler performs in a room with a ceiling 2m abouve hand level. A. what is the maximum upward speed she can give the ball without hitting the celing.
B. what is the time spent in the air before the ball is caught?
B. what is the time spent in the air before the ball is caught?
Answers
A.
Equate potential and kinetic energies:
potential energy = mgh = mg(2) N-m
where g = acceleration due to gravity = 9.8 m/s²
kinetic energy = (1/2)mv²
Equate energies:
mgh = (1/2)mv²
solve for v (m/s)
B. t = v/g (deceleration by gravity)
Equate potential and kinetic energies:
potential energy = mgh = mg(2) N-m
where g = acceleration due to gravity = 9.8 m/s²
kinetic energy = (1/2)mv²
Equate energies:
mgh = (1/2)mv²
solve for v (m/s)
B. t = v/g (deceleration by gravity)
(A) 6.3m/s
(B)1.3 s
(B)1.3 s
Related Questions
If a juggler throws a ball (10cm in diameter) 2.4m vertically above the level of his hand to the cei...
A juggler performs in a room with a ceiling that is 2.4 m above the level of his hands. He throws a...
A juggler performs in a room with a ceiling 2.71 m above hand level. What is the maximum upward spee...
circus juggler performs an act with balls that he tosses with his right hand and catches with his le...