Asked by vial

A juggler throws a bowling pin straight up with an initial speed of 8.20 m/s. How much time elapses until the bowling pin returns to the juggler's hand

Answers

Answered by oobleck
time to the top is when
v = 8.20 - 9.81t = 0
find t, then double that, since the pin has to fall back to the ground.
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