Asked by vial
A juggler throws a bowling pin straight up with an initial speed of 8.20 m/s. How much time elapses until the bowling pin returns to the juggler's hand
Answers
Answered by
oobleck
time to the top is when
v = 8.20 - 9.81t = 0
find t, then double that, since the pin has to fall back to the ground.
v = 8.20 - 9.81t = 0
find t, then double that, since the pin has to fall back to the ground.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.