Asked by leila
A juggler throws a ball from height of 0.950 m with a vertical velocity of +5.50 m/s and misses it on the way down. What is its velocity when it hits the ground?
Answers
Answered by
Henry
Vf = Vo + gt = 0,
5.5 + (-9.8)t = 0,
5.5 - 9.8t = 0,
9.8t = 5.5,
t = 5.5 / 9.8 = 0.56 s = time to reach max. height.
d = Vo - 4.9t^2,
d = 5.5 - 4.9(0.56)^2,
d = 5.5 - 1.54 = 3.96 m = max. height reached.
d(tot.) = 3.96 + 0.95 = 4.91 m above
gnd.
Vf^2 = Vo^2 + 2gd,
Vf^2 = o + 2 * 9.8 * 4.91,
Vf^2 = 96.3,
Vf = 9.81 m. = Velocity when it hits the gnd.
5.5 + (-9.8)t = 0,
5.5 - 9.8t = 0,
9.8t = 5.5,
t = 5.5 / 9.8 = 0.56 s = time to reach max. height.
d = Vo - 4.9t^2,
d = 5.5 - 4.9(0.56)^2,
d = 5.5 - 1.54 = 3.96 m = max. height reached.
d(tot.) = 3.96 + 0.95 = 4.91 m above
gnd.
Vf^2 = Vo^2 + 2gd,
Vf^2 = o + 2 * 9.8 * 4.91,
Vf^2 = 96.3,
Vf = 9.81 m. = Velocity when it hits the gnd.
Answered by
kaylee
can you please help me with this identical problem?
A juggler throws a ball from height of 0.950 m with a vertical velocity of +4.25 m/s and misses it on the way down. What is its velocity when it hits the ground?
A juggler throws a ball from height of 0.950 m with a vertical velocity of +4.25 m/s and misses it on the way down. What is its velocity when it hits the ground?
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