Question
A juggler tosses a ball h = 2 m into the air with one hand and catches it with the other hand at the same level. Neglecting air resistance, how long is the ball in the air?
Answers
h=1/2gt
-2m=1/2gt
-4m=gt
-4m=(-9.8m/s^2)t
-4/(-9.8m/s^2)=t
-2m=1/2gt
-4m=gt
-4m=(-9.8m/s^2)t
-4/(-9.8m/s^2)=t
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