Asked by Chris
A juggler tosses a ball h = 2 m into the air with one hand and catches it with the other hand at the same level. Neglecting air resistance, how long is the ball in the air?
Answers
Answered by
Rose
h=1/2gt
-2m=1/2gt
-4m=gt
-4m=(-9.8m/s^2)t
-4/(-9.8m/s^2)=t
-2m=1/2gt
-4m=gt
-4m=(-9.8m/s^2)t
-4/(-9.8m/s^2)=t
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