Question

Suppose a basketball player is an excellent free throw shooter and makes 91% of his free throws (i.e., he has a 91% chance of making a single free throw). Assume that free throw shots are independent of one another. Suppose this player shoots five free throws. Find the probability that he makes all five throws.

Answer 1

hey im NOT sure, but i think it's 45.5% because 5 x 0.91 = 45.5

Answer 2

The probability that he makes five out of his five shots
= (.91)(.91)(.91)(.91)(.91)
= (.91)^5
= .624 or 62.4%