Question

If a pro basketball player has a vertical leap of about 35 inches what is his hang-time? Use the hang-time function V=48T^2. Thank you I did mess up the typing last time didn't I?

Answer 1

If a pro basketball player has a vertical leap of about 35 inches, what is his hang-time? Using the hang-time function
V = 48T^2

Answer 2

I don't know how valid your equation is, but nevertheless, ...

35=48t^2
t^2 = .7291666..
t = ±.8539


but time is a positive number, so
his "hangtime" is 2(.854)units of time
or 1.7 units

(you don't say what t is)