If a basketball player has a vertical leap of 1.29 m , then what is his takeoff speed and his hang time ( total time to move upwards to the peak and then return to the ground ) ?

Answer 1

time rising: 4.9t^2 = 1.29
double that for total hang time.

v = 9.8t

Answer 2

Hello sir thank you for answering but I can't seem to find how we got the v ( velocity ) to be as 9.8 ... Isn't that the acceleration

Answer 3

distance: s = 1/2 at^2
speed: v = at