Asked by emm

A basketball player is trying to make a half-court jump shot and releases the ball at the height of the basket. Assuming that the ball is launched at 51 degrees, 14.0 m from the basket what speed must the player give the ball?

So far I found the Vy to be 8.55 m/s...but I don't know where to go from there.
Answered by bobpursley
If you have vy, the launch velocity is vy/sin51 if I read the launch angle correctly.
Answered by emm
I'm guessing I found the Vy correctly. I use Cos(51)=7/H which gave me 8.55.

So if I use Vy/Sin(51) that gives me...11??

Thanks!
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