evaluate the integral:

Question

integral of ((1-x)/x)^2 dx

Answer 1

Expand the integrand to:
1/x^2 -2/x + 1

The integral ia the sum of the integrals of each term

1/x - 2 lnx + x (+ any constant)

Answer 2

integral of ((1-x)/x)^2 dx
= integral of (1-2x+x^2)/(x^2) dx
= integral of (1/x^2 - 2/x + 1) dx
= -1/x - 2(lnx) + x + C

Answer 3

Reiny is correct. I missed a sign on one term. wls