Asked by Adam
evaluate the integral:
integral of ((1-x)/x)^2 dx
integral of ((1-x)/x)^2 dx
Answers
Answered by
drwls
Expand the integrand to:
1/x^2 -2/x + 1
The integral ia the sum of the integrals of each term
1/x - 2 lnx + x (+ any constant)
1/x^2 -2/x + 1
The integral ia the sum of the integrals of each term
1/x - 2 lnx + x (+ any constant)
Answered by
Reiny
integral of ((1-x)/x)^2 dx
= integral of (1-2x+x^2)/(x^2) dx
= integral of (1/x^2 - 2/x + 1) dx
= -1/x - 2(lnx) + x + C
= integral of (1-2x+x^2)/(x^2) dx
= integral of (1/x^2 - 2/x + 1) dx
= -1/x - 2(lnx) + x + C
Answered by
drwls
Reiny is correct. I missed a sign on one term. wls
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