Asked by Anonymous
Evaluate the indefinite integral.
∫ sec^3x tanx dx
I let u=tanx
took derivative..
du=sec^2x dx
..now what??
∫ sec^3x tanx dx
I let u=tanx
took derivative..
du=sec^2x dx
..now what??
Answers
Answered by
helper
sec^3 x tan x dx
| = integral symbol
Rewrite as
| sec^2 x sec x tan x dx
u = sec x
du = sec x tan x
| u^2 du
1/3 u^3 + C
Substitute back in, u = sec x
1/3 sec^3 x + C
| = integral symbol
Rewrite as
| sec^2 x sec x tan x dx
u = sec x
du = sec x tan x
| u^2 du
1/3 u^3 + C
Substitute back in, u = sec x
1/3 sec^3 x + C
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