Asked by Z32
Evaluate the indefinite integral:
x^2 / (3-4x^3)^6
I got -1/(60(4x^3-3))^5 but it's not right.
x^2 / (3-4x^3)^6
I got -1/(60(4x^3-3))^5 but it's not right.
Answers
Answered by
MathMate
Your answer is almost right except that some parentheses are in the wrong places.
Verify the parentheses.
Also, if the question asks to simplify the answer, you may be expected to remove the negative sign by switching the order of the terms in the denominator (to (3-4x³).
Unfortunately computer answers are sometimes quite one-track minded.
Verify the parentheses.
Also, if the question asks to simplify the answer, you may be expected to remove the negative sign by switching the order of the terms in the denominator (to (3-4x³).
Unfortunately computer answers are sometimes quite one-track minded.
Answered by
Z32
The parenthesis are in the wrong spot? I still can't figure it out.
Answered by
Z32
Oh, okay. I got it.
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