Asked by monica
Evaluate the indefinite integral as an infinite series.
[cos(x)-1]/x dx
[cos(x)-1]/x dx
Answers
Answered by
Anonymous
Hey, get used to this
cos u --> 1 - u^2/2! + .....
routine
and the e^u --> 1
as u---> 0
Both of your problems are the same.
cos u --> 1 - u^2/2! + .....
routine
and the e^u --> 1
as u---> 0
Both of your problems are the same.
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