I read your ((x^4 -2 +x)3x^-1) as
(3/x)(x^4 + x - 2)
= 3x^3 + 3 - 6/x
then ∫ (3x^3 + 3 - 6/x) dx
= (3/4)x^4 + 3x - 6lnx + c
Let me know if you meant otherwise and type it correctly
Evaluate the indefinite integral
1.((x^4 -2 +x)3x^-1)
1 answer