Question

Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)
Responses

92+16x=104+13x ; x=6

92−16x=104−13x ; x=−4

92+16x=104+13x ; x=4

104+16x=92+13x ; x=4

Answer 1

The correct equation to show when the two machines will have filled the same number of cans of soup is:

92 + 16x = 104 + 13x

Simplifying this equation, we get:

3x = 12

Dividing both sides of the equation by 3, we get:

x = 4

Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.