two machines at a factory of filling cans of soap. One machine has 92 cans of soap. It fills out a rate of 16 cans per minute the second factory has 104 cans of soap. It fills out a rate of 13 cans per minute write an equation to solve.

Answer 1

To find out when both machines will empty their cans of soap, we can set up equations for the time each machine takes to fill all the cans.

Let \( t \) represent the time in minutes.

For the first machine:

• Initial number of cans: 92
• Filling rate: 16 cans per minute

The equation for the first machine can be expressed as: \[ 92 - 16t = 0 \]

For the second machine:

• Initial number of cans: 104
• Filling rate: 13 cans per minute

The equation for the second machine can be expressed as: \[ 104 - 13t = 0 \]

Now we can solve each equation for \( t \):

1. For the first machine: \[ 92 - 16t = 0 \ 16t = 92 \ t = \frac{92}{16} = 5.75 \text{ minutes} \]

2. For the second machine: \[ 104 - 13t = 0 \ 13t = 104 \ t = \frac{104}{13} = 8 \text{ minutes} \]

Thus, the two machines will empty their cans of soap in 5.75 minutes and 8 minutes, respectively.