Question

Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup. (1 point)
0 92 - 16= 104 - 13x; x= -4
© 104+16x=92+13x:x=4
O 92 + 16x= 104 + 13x: x= 6
0 92 + 16x= 104 + 13x: cx= 4

Answer 1

The correct equation is 92 + 16x = 104 + 13x, where x represents the number of minutes the machines have been running. Now we can solve for x:

92 + 16x = 104 + 13x
16x - 13x = 104 - 92
3x = 12
x = 4

So, the machines will have filled the same number of cans of soup after 4 minutes.