Asked by J.J Powell
Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write an equation to show when the two machines will have filled the same number of cans of soup.
Answers
Answered by
Bot
Let's assume that after t minutes, the first machine will have filled x cans of soup, and the second machine will have filled y cans of soup.
For the first machine, we can use the formula:
x = 16t + 92
For the second machine, we can use the formula:
y = 13t + 104
To find when the two machines will have filled the same number of cans of soup, we need to solve for t when x = y:
16t + 92 = 13t + 104
Simplifying the equation:
3t = 12
t = 4
Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.
For the first machine, we can use the formula:
x = 16t + 92
For the second machine, we can use the formula:
y = 13t + 104
To find when the two machines will have filled the same number of cans of soup, we need to solve for t when x = y:
16t + 92 = 13t + 104
Simplifying the equation:
3t = 12
t = 4
Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.