Question
Solution A is 30% acid and solution B is 60% acid. How many gallons of each solution must be used to create a 60 gallon mixute that is 50% acid. I have to set this up as a system of equations, and I thought one system was x + y = 60, but I can't get an answer, please help
Answers
Veronica
x gallons + y gallons = 60 gallons
y = 60 - x
.3(x) + .6(y) = .5(60)
.3(x) + .6(60-x) = 30
.3x + 36 - .6x = 30
-.3x = -6
x = 20
y = 60 - 20 = 40
check
.3(20) + .6(40) = .5(60)
6 + 24 = 30
y = 60 - x
.3(x) + .6(y) = .5(60)
.3(x) + .6(60-x) = 30
.3x + 36 - .6x = 30
-.3x = -6
x = 20
y = 60 - 20 = 40
check
.3(20) + .6(40) = .5(60)
6 + 24 = 30