Asked by skye

the lab keeps two acid solutions on hand. one is 20% and the other is 35%. how much 20% and how much 35% acid solution should be used to prepare 25 liters of a 26% solution?
Answered by Reiny
amount of 20% solution ---- x L
amount of 35% solution ---- 25-x L

.20x + .35(25-x) = .26(25)
times 100
20x + 35(25-x) = 26(25)
20x + 875 - 35x = 650
-15x = -225
x = 15

so 20% solution is 15 L
and of the 35% solution we need 25-15 or 10 L




Answered by Anonymous
how do I set up this problem for linear equation 20x+.25=37


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