Question

A 10% acid solution is to be mixed with a 50% solution to get 200 liters of a 20% solution. How many liters of each solution should be used?

Answer 1

.1x + .5(200-x) = .2(200)
.1x + 100 -.5x = 40
-.4x + 100 = 40
-.4x + 100-100 = 40-100
-.4x = -60
x = 150
10% at 150 and 50% at 50

Answer 2

Thank you Kuai!