Question
If the pH of a nitric acid solution is 2.34, then what is the molarity of nitric acid in the solution?
A. 1.6 × 10-4 M
B. 3.8 × 10-3 M
C. 2.2 × 10-2 M
D. 4.6 × 10-3 M
A. 1.6 × 10-4 M
B. 3.8 × 10-3 M
C. 2.2 × 10-2 M
D. 4.6 × 10-3 M
Answers
DrBob
pH = -log(H^+).
Substitute and solve for (H^+). That will be the molarity in mols/L.
Substitute and solve for (H^+). That will be the molarity in mols/L.
Drbob hater
Oh Robert......
Leilani
Bruh js answer the question someone
Leo
Bob was right, just annoying that you refuse to actually answer it. Holy we're only here cus we don't wanna answer it all the time.
ANYWAYS:
pH = -Log(H^+)
2.34 = -Log(H^+)
-2.34 = Log(H^+) [Divided both sides by -1]
H^+ = 10^-2.34
H^+ = 4.6 x 10^-3
FINAL ANSWER IS: Option D
ANYWAYS:
pH = -Log(H^+)
2.34 = -Log(H^+)
-2.34 = Log(H^+) [Divided both sides by -1]
H^+ = 10^-2.34
H^+ = 4.6 x 10^-3
FINAL ANSWER IS: Option D