If the pH of a nitric acid solution is 2.34, then what is the molarity of nitric acid in the solution?

Question

A. 1.6 × 10-4 M
B. 3.8 × 10-3 M
C. 2.2 × 10-2 M
D. 4.6 × 10-3 M

Answer 1

pH = -log(H^+).
Substitute and solve for (H^+). That will be the molarity in mols/L.

Answer 2

Oh Robert......

Answer 3

Bruh js answer the question someone

Answer 4

Bob was right, just annoying that you refuse to actually answer it. Holy we're only here cus we don't wanna answer it all the time.

ANYWAYS:
pH = -Log(H^+)
2.34 = -Log(H^+)
-2.34 = Log(H^+) [Divided both sides by -1]
H^+ = 10^-2.34
H^+ = 4.6 x 10^-3

FINAL ANSWER IS: Option D