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DrBob222 millimols HF = mL x M = 500 mL x 0.43M = 215
mmols F^- = 500 mL x 0.45M = 225
40 mL x 0.1M NaOH = 4 millimols.
...........HF + OH^- ==> F^- H2O
initial...215....0......225......
add.............4.0............
change...-4.....-4........+4.........
equil....211......0.....229
Substitute the equil line from the ICE chart into the HH equation and solve for pH.