Question
26. How many grams of NaOH are required to prepare 350cm3 of 1.25M NaOH
solution?
solution?
Answers
GPT 3.5
To find the number of grams of NaOH required, we can use the formula:
grams = (volume (in liters) * molarity * molar mass).
First, we need to convert the volume of the solution in cm3 to liters:
350 cm3 = 350/1000 = 0.35 liters.
Next, we can substitute the given values into the formula:
grams = (0.35 liters * 1.25 mol/l * 40 g/mol) = 0.35 * 1.25 * 40 = 17.5 grams.
Therefore, 17.5 grams of NaOH are required to prepare 350 cm3 of 1.25M NaOH solution.
grams = (volume (in liters) * molarity * molar mass).
First, we need to convert the volume of the solution in cm3 to liters:
350 cm3 = 350/1000 = 0.35 liters.
Next, we can substitute the given values into the formula:
grams = (0.35 liters * 1.25 mol/l * 40 g/mol) = 0.35 * 1.25 * 40 = 17.5 grams.
Therefore, 17.5 grams of NaOH are required to prepare 350 cm3 of 1.25M NaOH solution.