Asked by Alice
If 4.56 grams of NaOH and 56.3 grams of Ca(OH)2 are added to enough water to make 1.50 L of solution, what will the pH be?
Answers
Answered by
DrBob222
Start by converting grams to moles. moles = grams/molar mass.
Ca(OH)2 is not all that soluble but since it is make a SOLUTION, I assume it is that soluble.
moles OH from Ca(OH)2 = M x L, then twice that because there two OH ions per mole Ca(OH)2.
mols NaOH = M x L.
Add all the moles together, then
M = total moles/total volume in liters.
Finally, convert OH to pOH, then to pH is the way I would do it.
Ca(OH)2 is not all that soluble but since it is make a SOLUTION, I assume it is that soluble.
moles OH from Ca(OH)2 = M x L, then twice that because there two OH ions per mole Ca(OH)2.
mols NaOH = M x L.
Add all the moles together, then
M = total moles/total volume in liters.
Finally, convert OH to pOH, then to pH is the way I would do it.
Answered by
Alice
OK thank you so much! I was wondering whether or not there would be 2 OH ions to account for. Thanks again!
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