Asked by Sarah

a fun loving 11.4kg otter slides up a hill and then back down to the same place. If she starts up at 5.75 m/s and returns at 3.75 m/s, how much mechanical energy did she lose on the hill and what happened to that energy

Answers

Answered by bobpursley
Figure the KE at start, subtract the KE at the finish, that is the friction loss.
Answered by Sarah
so i did Ki= 1/2mv^2 = 1/2(11.4kg)(5.75 m/s)2 = 188.45 J

Kf= 1/2mv^2
1/2(11.4kg)(3.75m/s)2= 80.15 J

so I took 188.45 - 80.15 and got 108 J is this correct
Answered by bobpursley
yes
Answered by Sarah
Thank you!
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