A 2.0Kg otter starts from rest at the top of a muddy incline 85 cm long and slides down to the bottom in .50s. What net force acts on the otter along the incline?

The force (F) equals the mass (M= 2.0 kg) times the acceleration.

If it travels 0.85 m in t = 0.50 s, the acceleration a is given by solving
0.85 = (1/2) a t^2 = = (a/2)*0.25
a = 6.8 m/s^2

Solve for F

13.6 n

givens:M=2.0kg,vi=0m/s,displacement=85cm(0.85m),t=0.50s.
formula=average acceleration=average velocity/total time
>>average velocity=displacement/time
>>average velocity=0.85/0.5=1.7m/s
>>average acceleration=1.7/0.5=3.4m/s^2
force=mass*acceleration
force=2.0*3.4=6.8N

6.8n

To find the net force acting on the otter along the incline, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

First, let's find the acceleration of the otter. We can use the equation of motion that relates the distance traveled, time taken, and acceleration:

distance = initial velocity × time + (1/2) × acceleration × time^2

In this case, the otter starts from rest, so the initial velocity is 0:

85 cm = 0 × 0.5 + (1/2) × acceleration × (0.5)^2

Simplifying the equation:

85 = 0 + (0.25/2) × acceleration

85 = 0.125 × acceleration

Now, solve for acceleration:

acceleration = 85 / 0.125

acceleration = 680 m/s^2

Next, we can calculate the net force acting on the otter using Newton's second law:

net force = mass × acceleration

mass = 2.0 kg (given)

net force = 2.0 kg × 680 m/s^2

net force = 1360 N

Therefore, the net force acting on the otter along the incline is 1360 Newtons.