Asked by Michael
A 1.9 kg otter starts from rest at the top of a muddy incline 84.1 cm long and slides down to the bottom in 0.60 s.
What net external force acts on the otter along the incline?
Answer in units of N.
What net external force acts on the otter along the incline?
Answer in units of N.
Answers
Answered by
Henry
d = 0.5at^2 = 0.841m.
0.5a(0.6)^2 = 0.841,
0.18a = 0.841,
a = 0.841 / 0.18 = 4.67.2m/s^2.
F = ma = 1.9 * 4.67 = 8.88N.
0.5a(0.6)^2 = 0.841,
0.18a = 0.841,
a = 0.841 / 0.18 = 4.67.2m/s^2.
F = ma = 1.9 * 4.67 = 8.88N.
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