Asked by Paul
A bus starts from rest at a bus stop and accelerates at a rate of 1.12 m/s^2 for 11.0s. It runs at constant speed for 80.0 s and slows at a rate 1.20 m/s^2 until it stops at the next bus stop. (a) What is the maximum speed attained. (b) Find the total distance covered.
Answers
Answered by
Anonymous
vmax is just after the 11seconds
vmax= a*t
distance covered:
break it up into three times
accelerating
constant speed
deaccelerating.
vmax= a*t
distance covered:
break it up into three times
accelerating
constant speed
deaccelerating.
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