Question

The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory.

What volume (L) of O2 gas at 25 °C and 1.00 atm pressure is produced by the decomposition of 7.5 g of KClO3 (s)?

Here is my work:

V=nRT/P

.0611995 mol of O2 x .0821Latm/molL x298.15K / 1.0atm=1.498

Why is 1.498 incorrect?

Answer 1

.0611995 mol of KClO3 needed to be converted to .09179925 mol of O2 b/c of the coeficients

Answer 2

The answer is correct except for not being labeled and not rounded off correctly.

Answer 3

The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory.

2KClO3 (s) ® 2KCl (s) + 3O2 (g)

What volume (L) of O2 gas at 25°C and 1.00 atm pressure is produced by the decomposition of 7.5 g of KClO3 (s)?
Group of answer choices
4.5
3.7
7.5
11
2.2
THE ANSWER IS 2.24 ROUNDED TO 2.2