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Gweedo
Questions (9)
The problem:
Nitrogen can react with steam to form ammonia and nitrogen monoxide gas. A 20.0L sample of nitrogen at 173C and
2 answers
2,425 views
The question:
Formic acid when warmed with sulfuric acid, decomposes to water and carbon monoxide. HCHO2(l)-->H2O(l)+CO(g) If
1 answer
683 views
Here is the question:
A sample of an unknown volatile liquid was injected into a Dumas flask (mflask=27.0928g. Vflask=.104L) and
2 answers
3,613 views
Here is the question:
Automobile air bags use the decomposition of sodium azide as their source of gas for rapid inflation:
2 answers
6,375 views
Here is the question:
sodium hydride reacts with excess water to produce aqueous sodium hydroxide and hydrogen gas:
4 answers
1,670 views
The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory.
What volume (L) of O2 gas at 25
3 answers
4,711 views
Can someone pleas help I have this assignment and the only question I cannot figure out is to describe the hybridization of all
2 answers
662 views
Describe how would you prepare .005M solution of IO3^-1 starting with potassium iodate KIO3
3 answers
977 views
Correct these sentences, if necessary!
2) Tommy Boy acted like a child and was treated like a child. 4) Tommy Callahan was a
1 answer
713 views
Answers (13)
Please disregard I finally figured it out.
DISREGARD
Thank you that was exactly what I was looking for.
Once again thank you Bob, I think my brain is fried for the day. I would stop if I did not have 4 more questions to go. Hopefully I can get them on my own now that I figured out the calculator issues I was haveing.
Thank you so much for sticking with me on this, for some reason I am putting the entire problem into my TI-83 and it is coming up with those large numbers. I do not get why it is doing that but now I got the right answer.
Ok so I took the 1.01 atm H2 and subtracted the .03684atm H2O=.97316 Then put that in the equation I did earlier. n=PV/RT P=.97316 R=.0821 V=.982 L T=301.15 K (.97316atm H2)(.989L H2)/(.0821 Latm/mol L)(301.15k H2)==3505.383 mol H2 3505.383 mol H2 =
.0611995 mol of KClO3 needed to be converted to .09179925 mol of O2 b/c of the coeficients
disregard, I found the answer
Thank you
I answered this in another post
i GOT THAT FROM TOP20ECONOMICS . COM i CANNOT PUT IN THE LINK i AM NEW TO THE SITE AND UNSURE WHAT THE RULES ARE SO I HOPE THIS DOES NOT GET US IN TROUBLE
ingrimayne . com / econ / TOC . html HOPE THIS HELPS
I am thinking I need to work backwords on this problem so here is my math if anyone can confirm it for me that would be great. .005M IO3-1 * .5 Lsolutions = .0025 moles of IO3-1 Then I took .0025 mol IO3= .0025 mol KIO3 Then I took .0025 mol KIO3 * 214.001