2FeCl3 3.785g   2.175g
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|
v
2Fe 1.302   x
+
3Cl2 2.483   y
I would do it this way.
For Fe, x = 1.302 x (2.175/3.785) = 0.758 g
For Cl2 2.175-0.758 = 1.427 g
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|
v
2Fe 1.302   x
+
3Cl2 2.483   y
I would do it this way.
For Fe, x = 1.302 x (2.175/3.785) = 0.758 g
For Cl2 2.175-0.758 = 1.427 g
First, let's determine the proportion of iron and chlorine produced by decomposing 3.785 g of iron (III) chloride:
Amount of iron produced = 1.302 g
Amount of chlorine produced = 2.483 g
Now, let's set up a proportion to find out the amount of iron and chlorine produced when 2.175 g of iron (III) chloride decomposes:
(1.302 g iron) / (3.785 g iron (III) chloride) = (x g iron) / (2.175 g iron (III) chloride)
Cross-multiplying, we get:
(1.302 g iron) * (2.175 g iron (III) chloride) = (x g iron) * (3.785 g iron (III) chloride)
Simplifying, we have:
x g iron = (1.302 g iron) * (2.175 g iron (III) chloride) / (3.785 g iron (III) chloride)
Evaluating this expression gives:
x g iron = 0.75 g iron
Therefore, when 2.175 g of iron (III) chloride decomposes, approximately 0.75 g of iron is produced.
Similarly, we can find the amount of chlorine produced using the same approach:
(x g chlorine) / (2.175 g iron (III) chloride) = (2.483 g chlorine) / (3.785 g iron (III) chloride)
Cross-multiplying and simplifying, we have:
x g chlorine = (2.483 g chlorine) * (2.175 g iron (III) chloride) / (3.785 g iron (III) chloride)
Evaluating this expression gives:
x g chlorine = 1.43 g chlorine
Therefore, when 2.175 g of iron (III) chloride decomposes, approximately 1.43 g of chlorine is produced.
In summary, when 2.175 g of iron (III) chloride decomposes, approximately 0.75 g of iron and 1.43 g of chlorine are produced.