Question
Nitrogen gas reacts with hydrogen gas to produce ammonia via the following reaction:
N2 (g) + 3H2(g) →2NH3 (g)
How many grams of H2 are needed to react with 3.80 g of N2?
Express your answer with the appropriate units
N2 (g) + 3H2(g) →2NH3 (g)
How many grams of H2 are needed to react with 3.80 g of N2?
Express your answer with the appropriate units
Answers
Answered by
GPT 3.5
To solve this problem, we need to use the stoichiometry of the reaction. From the balanced equation, we can see that 3 moles of hydrogen gas (H2) are required to react with 1 mole of nitrogen gas (N2).
1 mole of N2 has a molar mass of 14.01 g/mol, so 3.80 g of N2 is equal to 3.80 g / 14.01 g/mol = 0.271 mol of N2.
Therefore, we need 3 times that amount of H2, so we need 0.271 mol × 3 = 0.813 mol of H2.
The molar mass of H2 is 2.02 g/mol, so 0.813 mol of H2 is equal to 0.813 mol × 2.02 g/mol = 1.64 g of H2.
Therefore, 1.64 grams of H2 are needed to react with 3.80 g of N2.
1 mole of N2 has a molar mass of 14.01 g/mol, so 3.80 g of N2 is equal to 3.80 g / 14.01 g/mol = 0.271 mol of N2.
Therefore, we need 3 times that amount of H2, so we need 0.271 mol × 3 = 0.813 mol of H2.
The molar mass of H2 is 2.02 g/mol, so 0.813 mol of H2 is equal to 0.813 mol × 2.02 g/mol = 1.64 g of H2.
Therefore, 1.64 grams of H2 are needed to react with 3.80 g of N2.