Asked by Leslie
Nitrogen reacts with powdered aluminum according to the reaction:
2Al(s)+N2(g)→2AlN(s)
How many liters of N2 gas, measured at 892 torr and 98 ∘C, are required to completely react with 17.8 g of Al?
2Al(s)+N2(g)→2AlN(s)
How many liters of N2 gas, measured at 892 torr and 98 ∘C, are required to completely react with 17.8 g of Al?
Answers
Answered by
DrBob222
mols Al = grams/atomic mass = ?
Using the coefficients in the balanced equation, convert mols Al to mols N2. That is mols Al x (1 mol N2/2 mols Al) = ?
Now use PV = nRT with the conditions listed to solve for V. Post your work if you get stuck.
Using the coefficients in the balanced equation, convert mols Al to mols N2. That is mols Al x (1 mol N2/2 mols Al) = ?
Now use PV = nRT with the conditions listed to solve for V. Post your work if you get stuck.
Answered by
Leslie
is this the right setup? (1.174) x V= (36)(0.0821)(371)
Answered by
Leslie
correction: (1.174) x V= (8.9)(0.0821)(371)
Answered by
DrBob222
The set up is OK but n doesn't look right to me.
Answered by
Leslie
How do you calculate n specifically?
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