Asked by Leslie

Nitrogen reacts with powdered aluminum according to the reaction:
2Al(s)+N2(g)→2AlN(s)

How many liters of N2 gas, measured at 892 torr and 98 ∘C, are required to completely react with 17.8 g of Al?
Answered by DrBob222
mols Al = grams/atomic mass = ?
Using the coefficients in the balanced equation, convert mols Al to mols N2. That is mols Al x (1 mol N2/2 mols Al) = ?
Now use PV = nRT with the conditions listed to solve for V. Post your work if you get stuck.
Answered by Leslie
is this the right setup? (1.174) x V= (36)(0.0821)(371)
Answered by Leslie
correction: (1.174) x V= (8.9)(0.0821)(371)
Answered by DrBob222
The set up is OK but n doesn't look right to me.
Answered by Leslie
How do you calculate n specifically?
There are no AI answers yet. The ability to request AI answers is coming soon!