Question

Nitrogen gas reacts with hydrogen gas to produce ammonia via the following reaction:
N2 (g) + 3H2(g) →2N3 (g)
• Part A
If you have 3.32 g of H2, how many grams of NH3 can be produced?
Express your answer with the appropriate units.

Answer 1

To solve this problem, we need to use stoichiometry and the given balanced equation.

From the balanced equation, we can see that the ratio between H2 and NH3 is 3:2.

First, we need to convert the given mass of H2 to moles:
Molar mass of H2 = 2 g/mol
Number of moles of H2 = 3.32 g / 2 g/mol = 1.66 mol

Next, we can use the mole ratio to find the number of moles of NH3 produced:
1 mol H2 : 2 mol NH3
1.66 mol H2 : x mol NH3

Using the ratio, we can set up a proportion:
1.66 mol H2 / (1 mol H2 : 2 mol NH3) = x mol NH3

Simplifying the proportion:
x = 1.66 mol H2 * (2 mol NH3 / 1 mol H2) = 3.32 mol NH3

Finally, we need to convert the moles of NH3 to grams:
Molar mass of NH3 = 17 g/mol
Mass of NH3 = 3.32 mol NH3 * 17 g/mol = 56.44 g

Therefore, 3.32 g of H2 can produce 56.44 g of NH3.