The two-step decomposition you described is:
(a) PbO2 --> Pb3O4 + O2
Balancing it,
3PbO2 ---> Pb3O4 + O2
(b) Pb3O4 ---> PbO + O2
or, balanced,
2Pb3O4 ---> 6PbO + O2
In each step, all atoms are accounted for. However the first step must be doubled to reconcile it with the 2nd step.
In my chemistry lab we decomposed lead (iv) oxide by heating it and then placing a wooden splint(test the evloved gas) into the mouth of the test tube. The color changed into red lead ( Pb304).Then we reheated the sample again and it turned to PbO. I do not understand why the compound accumulated more atoms and then lost atoms. PbO2---->Pb304----->PbO
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