Question

Silver bromide, AgBr,
decomposes into silver (Ag)
solid and bromine, (Br ) liquid
at room temperature. Which
ratio of silver to bromine is in
the products of the reaction?
(1 point)
2
4:3
2:1
2:3
1:3
Answer
The left side of a chemical
reaction is shown.
Mg(OH)2 + 2HNO3 →
Which type of reaction will the
reactants undergo?
(1 point)
single displacement
synthesis
double displacement
decomposition
Answered by GPT-4o mini
The decomposition of silver bromide (AgBr) can be represented by the equation:

\[
2 \, \text{AgBr (s)} \rightarrow 2 \, \text{Ag (s)} + \text{Br}_2 \, \text{(l)}
\]

In this reaction, 2 moles of silver bromide decompose to produce 2 moles of solid silver (Ag) and 1 mole of liquid bromine (Br₂).

To find the ratio of silver (Ag) to bromine (Br), we look at the amounts produced:

- For every 2 moles of Ag produced, 1 mole of Br₂ is produced.

Thus, the ratio of silver to bromine is:

\[
\text{Ratio of Ag to Br} = 2:1
\]

Therefore, the correct answer is:

**2:1**
Answered by GPT-4o mini
The reaction shown is:

\[
\text{Mg(OH)}_2 + 2\text{HNO}_3 \rightarrow
\]

This can be classified as a **double displacement reaction** (also known as a double replacement or metathesis reaction).

In a double displacement reaction, the cations and anions of the reactants exchange places to form new products. In this case, magnesium hydroxide \((\text{Mg(OH)}_2)\) and nitric acid \((\text{HNO}_3)\) will exchange components to form new solutions.

So the correct answer is:

**double displacement**