Asked by Anonymous
When HgO is heated, it decomposes into elemental mercury and molecular oxygen gas. If 64.0 g of Hg is obtained from 85.0 g of the oxide, what is the percent yield of the reaction?
The balanced equation is 2HgO > 2Hg + 02.
The balanced equation is 2HgO > 2Hg + 02.
Answers
Answered by
Anonymous
2HgO--->O2+2Hg
85g(HgO)*1mol/(200.59+16)g* 2molHg/2molHgO*200.59gHg/1molHg=78.721g
that is your theoretical yield
so 64.0g/78.721*100=81.3%yeild
85g(HgO)*1mol/(200.59+16)g* 2molHg/2molHgO*200.59gHg/1molHg=78.721g
that is your theoretical yield
so 64.0g/78.721*100=81.3%yeild