Asked by Anon
Ksp for AgBr is 5x10-13. What is the maximum concentration of silver ion that you can have in a 0.1 M solution of NaBr?
Answers
Answered by
DrBob222
........AgBr ==> Ag^+ + Br^-
I......solid.....0......0
C......solid.....x......x
E......solid.....x......x
........NaBr --> Na^+ +Br^-
I......0.1.......0.....0
C.....-0.1......0.1...0.1
E........0......0.1...0.1
Note that NaBr is completely dissociated while AgCl is not.
Write the Ksp expression for AgBr, and substitute the concentrations from thre above two equations.
(Ag^+) = x
(Br^-) = x from AgBr and 0.1 from NaBr
Solve for x = (Ag^+)
I......solid.....0......0
C......solid.....x......x
E......solid.....x......x
........NaBr --> Na^+ +Br^-
I......0.1.......0.....0
C.....-0.1......0.1...0.1
E........0......0.1...0.1
Note that NaBr is completely dissociated while AgCl is not.
Write the Ksp expression for AgBr, and substitute the concentrations from thre above two equations.
(Ag^+) = x
(Br^-) = x from AgBr and 0.1 from NaBr
Solve for x = (Ag^+)
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