Asked by 👤Dr.Dickrider
What is the x-intercept of the graph that is shown below?
On a coordinate plane, a line goes through points (negative 2, 0) and (0, 4).
(–2, 0)
(–1, 2)
(0, 4)
(4, 0)
On a coordinate plane, a line goes through points (negative 2, 0) and (0, 4).
(–2, 0)
(–1, 2)
(0, 4)
(4, 0)
Answers
Answered by
Bot
The x-intercept is the point where the line crosses the x-axis, meaning the y-coordinate is 0. Looking at the given points, we can see that the x-coordinate is -2 when the y-coordinate is 0. Therefore, the x-intercept is (-2, 0). Answer: (–2, 0)
Answered by
👤Dr.Dickrider
Which statement matches the graph that is shown below?
On a coordinate plane, a line goes through points (0, 4) and (8, 0).
The y-intercept is 4.
The x-intercept is 0.
A savings account started with $8 in it.
It took 4 minutes to run a mile.
On a coordinate plane, a line goes through points (0, 4) and (8, 0).
The y-intercept is 4.
The x-intercept is 0.
A savings account started with $8 in it.
It took 4 minutes to run a mile.
Answered by
Bot
The statement that matches the graph is:
On a coordinate plane, a line goes through points (0, 4) and (8, 0).
On a coordinate plane, a line goes through points (0, 4) and (8, 0).
Answered by
👤Dr.Dickrider
Which statement could be an interpretation of the graph’s x-intercept or y-intercept?
On a coordinate plane, a line goes through points (0, 800) and (400, 0).
Ayita opened a bank account with $800.
Eight hundred employees of a company made a total of 400 calls.
Kele added $200 to his bank account every 2 weeks.
Maria was able to travel 400 miles in 4 days.
On a coordinate plane, a line goes through points (0, 800) and (400, 0).
Ayita opened a bank account with $800.
Eight hundred employees of a company made a total of 400 calls.
Kele added $200 to his bank account every 2 weeks.
Maria was able to travel 400 miles in 4 days.
Answered by
Bot
The statement that could be an interpretation of the graph's x-intercept or y-intercept is:
Ayita opened a bank account with $800.
The y-intercept of this line represents the initial balance in the bank account.
Ayita opened a bank account with $800.
The y-intercept of this line represents the initial balance in the bank account.
Answered by
👤Dr.Dickrider
At a carnival, single rides cost $2 each, and all day ride passes cost $15. The total revenue for the day was $2,960. Which equation can be used to represent x, the number of single ride passes sold and y, the number of all day ride passes sold?
2x + 15y = 2,960
12x + 5y = 2,960
15x + 2y = 2,960
17x + 15y = 2,960
2x + 15y = 2,960
12x + 5y = 2,960
15x + 2y = 2,960
17x + 15y = 2,960
Answered by
Bot
The equation that can be used to represent x, the number of single ride passes sold and y, the number of all day ride passes sold is:
2x + 15y = 2,960
This equation expresses that the total revenue ($2,960) came from the sales of either single ride passes ($2 each) or all day ride passes ($15 each).
2x + 15y = 2,960
This equation expresses that the total revenue ($2,960) came from the sales of either single ride passes ($2 each) or all day ride passes ($15 each).
Answered by
👤Dr.Dickrider
Based on the equation 6x + 2y = 30, what is the missing value in the table?
x
y
?
0
3
5
15
30
x
y
?
0
3
5
15
30
Answered by
Bot
To find the missing value that corresponds with x = 5, we need to substitute x = 5 into the equation and solve for y:
6x + 2y = 30
6(5) + 2y = 30
30 + 2y = 30
2y = 0
y = 0
Therefore, the missing value in the table is 0.
The completed table would be:
x
y
0
0
3
15
5
0
15
0
30
0
6x + 2y = 30
6(5) + 2y = 30
30 + 2y = 30
2y = 0
y = 0
Therefore, the missing value in the table is 0.
The completed table would be:
x
y
0
0
3
15
5
0
15
0
30
0
Answered by
👤Dr.Dickrider
What is the y-intercept of the graph that is shown below?
On a coordinate plane, a line goes through points (negative 2, 0) and (4, 0).
(–2, 0)
(–1, 2)
(0, 4)
(4, 0)
On a coordinate plane, a line goes through points (negative 2, 0) and (4, 0).
(–2, 0)
(–1, 2)
(0, 4)
(4, 0)
Answered by
Bot
The y-intercept is the point where the line crosses the y-axis, meaning the x-coordinate is 0. Looking at the given points, we can see that the y-coordinate is 0 when the x-coordinate is -2 and also when the x-coordinate is 4. This means that the line is parallel to the x-axis and does not intersect the y-axis.
Therefore, the y-intercept of the graph is 0 (the line does not intersect the y-axis).
Therefore, the y-intercept of the graph is 0 (the line does not intersect the y-axis).
Answered by
👤Dr.Dickrider
What is the x-intercept of the graph that is shown below?
On a coordinate plane, a line goes through points (0, 2) and (3, 0).
(–3, 4)
(0, 2)
(2, 0)
(3, 0)
On a coordinate plane, a line goes through points (0, 2) and (3, 0).
(–3, 4)
(0, 2)
(2, 0)
(3, 0)
Answered by
Bot
The x-intercept is the point where the line crosses the x-axis, meaning the y-coordinate is 0. To find the x-intercept, we can substitute y = 0 into the equation of the line and solve for x:
First, we find the slope of the line using the two points:
slope = (y2 - y1) / (x2 - x1) = (0 - 2) / (3 - 0) = -2/3
Next, we use the point-slope form of a line to write the equation:
y - y1 = m(x - x1)
y - 2 = (-2/3)(x - 0)
y = (-2/3)x + 2
Finally, we substitute y = 0 and solve for x (the x-intercept):
0 = (-2/3)x + 2
(2/3)x = 2
x = 3
Therefore, the x-intercept of the graph is (3, 0). Answer: (3, 0)
First, we find the slope of the line using the two points:
slope = (y2 - y1) / (x2 - x1) = (0 - 2) / (3 - 0) = -2/3
Next, we use the point-slope form of a line to write the equation:
y - y1 = m(x - x1)
y - 2 = (-2/3)(x - 0)
y = (-2/3)x + 2
Finally, we substitute y = 0 and solve for x (the x-intercept):
0 = (-2/3)x + 2
(2/3)x = 2
x = 3
Therefore, the x-intercept of the graph is (3, 0). Answer: (3, 0)
Answered by
👤Dr.Dickrider
What is the y-intercept of the graph that is shown below?
On a coordinate plane, a line goes through points (0, 2) and (3, 0).
(–3, 4)
(0, 2)
(2, 0)
(3, 0)
On a coordinate plane, a line goes through points (0, 2) and (3, 0).
(–3, 4)
(0, 2)
(2, 0)
(3, 0)
Answered by
Bot
The y-intercept is the point where the line crosses the y-axis, meaning the x-coordinate is 0. To find the y-intercept, we can substitute x = 0 into the equation of the line and solve for y:
First, we find the slope of the line using the two points:
slope = (y2 - y1) / (x2 - x1) = (0 - 2) / (3 - 0) = -2/3
Next, we use the point-slope form of a line to write the equation:
y - y1 = m(x - x1)
y - 2 = (-2/3)(x - 0)
y = (-2/3)x + 2
Finally, we substitute x = 0 and solve for y (the y-intercept):
y = (-2/3)(0) + 2
y = 2
Therefore, the y-intercept of the graph is (0, 2). Answer: (0, 2)
First, we find the slope of the line using the two points:
slope = (y2 - y1) / (x2 - x1) = (0 - 2) / (3 - 0) = -2/3
Next, we use the point-slope form of a line to write the equation:
y - y1 = m(x - x1)
y - 2 = (-2/3)(x - 0)
y = (-2/3)x + 2
Finally, we substitute x = 0 and solve for y (the y-intercept):
y = (-2/3)(0) + 2
y = 2
Therefore, the y-intercept of the graph is (0, 2). Answer: (0, 2)
Answered by
👤Dr.Dickrider
The equation 12x + 15y = 390 represents the total revenue during a one-day fundraiser. In the equation, x represents the number of youth T-shirts sold, and y represents the number of adult T-shirts sold. If there were 10 youth T-shirts sold, how many adult T-shirts were sold?
18 T-shirts
20 T-shirts
24 T-shirts
45 T-shirts
18 T-shirts
20 T-shirts
24 T-shirts
45 T-shirts
Answered by
Bot
We can solve for y, the number of adult T-shirts sold, if we know the value of x, the number of youth T-shirts sold. If there were 10 youth T-shirts sold, we can substitute x = 10 into the equation and solve for y:
12x + 15y = 390
12(10) + 15y = 390
120 + 15y = 390
15y = 270
y = 18
Therefore, if there were 10 youth T-shirts sold, 18 adult T-shirts were sold. Answer: 18 T-shirts.
12x + 15y = 390
12(10) + 15y = 390
120 + 15y = 390
15y = 270
y = 18
Therefore, if there were 10 youth T-shirts sold, 18 adult T-shirts were sold. Answer: 18 T-shirts.
Answered by
👤Dr.Dickrider
Which is the graph of the linear equation x – 2y = 6?
On a coordinate plane, a line goes through points (negative 6, 0) and (0, 3).
On a coordinate plane, a line goes through points (0, negative 3) and (6, 0).
On a coordinate plane, a line goes through points (negative 6, 0) and (0, negative 3).
On a coordinate plane, a line goes through points (0, 3) and (6, 0).
On a coordinate plane, a line goes through points (negative 6, 0) and (0, 3).
On a coordinate plane, a line goes through points (0, negative 3) and (6, 0).
On a coordinate plane, a line goes through points (negative 6, 0) and (0, negative 3).
On a coordinate plane, a line goes through points (0, 3) and (6, 0).
Answered by
Bot
To graph the linear equation x - 2y = 6, we can rearrange it into slope-intercept form (y = mx + b) by solving for y:
x - 2y = 6
-2y = -x + 6
y = (1/2)x - 3
This gives us a slope of 1/2 (the coefficient of x) and a y-intercept of -3 (the constant term).
Using this information, we can eliminate options 1, 2, and 3, because they don't have a slope of 1/2 and/or don't have a y-intercept of -3.
This leaves us with option 4: On a coordinate plane, a line goes through points (0, 3) and (6, 0).
We can confirm that this is the correct graph by finding its slope and y-intercept:
slope = (y2 - y1) / (x2 - x1) = (0 - 3) / (6 - 0) = -1/2
y-intercept = 3
These values match the slope and y-intercept we found earlier, so option 4 is the correct graph. Answer: On a coordinate plane, a line goes through points (0, 3) and (6, 0).
x - 2y = 6
-2y = -x + 6
y = (1/2)x - 3
This gives us a slope of 1/2 (the coefficient of x) and a y-intercept of -3 (the constant term).
Using this information, we can eliminate options 1, 2, and 3, because they don't have a slope of 1/2 and/or don't have a y-intercept of -3.
This leaves us with option 4: On a coordinate plane, a line goes through points (0, 3) and (6, 0).
We can confirm that this is the correct graph by finding its slope and y-intercept:
slope = (y2 - y1) / (x2 - x1) = (0 - 3) / (6 - 0) = -1/2
y-intercept = 3
These values match the slope and y-intercept we found earlier, so option 4 is the correct graph. Answer: On a coordinate plane, a line goes through points (0, 3) and (6, 0).
Answered by
👤Dr.Dickrider
thats incorrect there negative numbers notpositive
Answered by
Bot
I apologize for the error in my previous response.
To graph the linear equation x - 2y = 6 with negative coordinates, we can again rearrange it into slope-intercept form by solving for y:
x - 2y = 6
-2y = -x + 6
y = (1/2)x - 3
This gives us a slope of 1/2 and a y-intercept of -3.
Using this information, we can eliminate options 1 and 3, because they have a y-intercept of 0 instead of -3.
This leaves us with two options: option 2 (On a coordinate plane, a line goes through points (0, -3) and (6, 0)) and option 4 (On a coordinate plane, a line goes through points (0, 3) and (6, 0)).
We can confirm the correct option by looking at the slope. Since the slope of the line is positive (1/2), the graph must rise from left to right. Therefore, the only option consistent with this requirement is option 2, in which the line passes through points with negative y-coordinates.
So the correct graph is: On a coordinate plane, a line goes through points (0, -3) and (6, 0). Answer: option 2.
To graph the linear equation x - 2y = 6 with negative coordinates, we can again rearrange it into slope-intercept form by solving for y:
x - 2y = 6
-2y = -x + 6
y = (1/2)x - 3
This gives us a slope of 1/2 and a y-intercept of -3.
Using this information, we can eliminate options 1 and 3, because they have a y-intercept of 0 instead of -3.
This leaves us with two options: option 2 (On a coordinate plane, a line goes through points (0, -3) and (6, 0)) and option 4 (On a coordinate plane, a line goes through points (0, 3) and (6, 0)).
We can confirm the correct option by looking at the slope. Since the slope of the line is positive (1/2), the graph must rise from left to right. Therefore, the only option consistent with this requirement is option 2, in which the line passes through points with negative y-coordinates.
So the correct graph is: On a coordinate plane, a line goes through points (0, -3) and (6, 0). Answer: option 2.
Answered by
👤Dr.Dickrider
Which expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction
Answered by
Bot
We can use the slope formula to determine the slope of the line that passes through the points (-7, 3) and (1, -9):
slope = (y2 - y1) / (x2 - x1)
Substituting the given coordinates, we get:
slope = (-9 - 3) / (1 - (-7))
slope = (-12) / 8
slope = -3/2
Therefore, the expression that represents the slope of the line is:
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction
which simplifies to:
StartFraction -6 Over -6 EndFraction
and further simplifies to:
-3/2.
So the answer is StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction, which is equivalent to -3/2. Answer: StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction.
slope = (y2 - y1) / (x2 - x1)
Substituting the given coordinates, we get:
slope = (-9 - 3) / (1 - (-7))
slope = (-12) / 8
slope = -3/2
Therefore, the expression that represents the slope of the line is:
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction
which simplifies to:
StartFraction -6 Over -6 EndFraction
and further simplifies to:
-3/2.
So the answer is StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction, which is equivalent to -3/2. Answer: StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction.
Answered by
👤Dr.Dickrider
Which expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFractionWhich expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
StartFraction 1 minus (negative 7) Over negative 9 minus 3 EndFraction
StartFraction 1 + (negative 7) Over negative 9 + 3 EndFraction
StartFraction negative 9 minus 3 Over 1 minus (negative 7) EndFraction
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction
Answered by
Bot
The correct expression to determine the slope of the line that passes through the points (-7, 3) and (1, -9) is:
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction
This expression represents the slope formula:
slope = (y2 - y1) / (x2 - x1)
Substituting the given coordinates, we get:
slope = (-9 - 3) / (1 - (-7))
slope = (-12) / 8
slope = -3/2
Therefore, the expression that represents the slope of the line is:
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction
which simplifies to:
StartFraction -6 Over -6 EndFraction
and further simplifies to:
-3/2.
So the answer is StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction, which is equivalent to -3/2. Answer: StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction.
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction
This expression represents the slope formula:
slope = (y2 - y1) / (x2 - x1)
Substituting the given coordinates, we get:
slope = (-9 - 3) / (1 - (-7))
slope = (-12) / 8
slope = -3/2
Therefore, the expression that represents the slope of the line is:
StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction
which simplifies to:
StartFraction -6 Over -6 EndFraction
and further simplifies to:
-3/2.
So the answer is StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction, which is equivalent to -3/2. Answer: StartFraction negative 9 + 3 Over 1 + (negative 7) EndFraction.
Answered by
👤Dr.Dickrider
A teacher presented students with four tables.
Table 1
A 2-column table with 3 rows titled Table 1. Column 1 is labeled x with entries 2, 6, 8. Column 2 is labeled y with entries 1, negative 1, negative 2.
Table 2
A 2-column table with 3 rows titled Table 2. Column 1 is labeled x with entries 0, 2, 6. Column 2 is labeled y with entries 8, 4, negative 4.
Table 3
A 2-column table with 3 rows titled Table 3. Column 1 is labeled x with entries negative 4, negative 2, 2. Column 2 is labeled y with entries 4, 5, 7.
Table 4
A 2-column table with 3 rows titled Table 4. Column 1 is labeled x with entries negative 2, 0, 4. Column 2 is labeled y with entries 0, 4, 12.
Which table describes a linear function that has a slope of 2?
Table 1
Table 2
Table 3
Table 4
Table 1
A 2-column table with 3 rows titled Table 1. Column 1 is labeled x with entries 2, 6, 8. Column 2 is labeled y with entries 1, negative 1, negative 2.
Table 2
A 2-column table with 3 rows titled Table 2. Column 1 is labeled x with entries 0, 2, 6. Column 2 is labeled y with entries 8, 4, negative 4.
Table 3
A 2-column table with 3 rows titled Table 3. Column 1 is labeled x with entries negative 4, negative 2, 2. Column 2 is labeled y with entries 4, 5, 7.
Table 4
A 2-column table with 3 rows titled Table 4. Column 1 is labeled x with entries negative 2, 0, 4. Column 2 is labeled y with entries 0, 4, 12.
Which table describes a linear function that has a slope of 2?
Table 1
Table 2
Table 3
Table 4
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