Question

y= x^2 +4x-5

x intercept- 4?
y intercept- -5?
vertex-? I don't know how to find the vertex.
axis of symmetry?

Answer 1

for y-intercept , let x = 0
so y = 0+0-5 = -5
y-intercept is -5

for x-intercept , let y = 0
x^2 + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5 or x = 1
the x-intercepts are -5 and 1

for vertex , complete the square
y = x^2 + 4x + 4 - 4- 5
= (x+2)^2 - 9
vertex is (-2,-9)

axis of symmetry: x = -2